My first experience of problem setting. It feels good when you see people think about your problem and come up with better solutions than yours ðŸ˜›

This problem is about math and primes. The link is this.

# Category Archives: Programming

# UVa Easy Problem List

StandardUVa(University of Valladolid) has one of the best online judges to start online problem solving. Here is a list of some easy problems from UVa for newbies.

**100, 119, 133, 136, 146, 272, 401, 409, 412, 440, 444, 446, 458, 468, 476, 488, 489, 490, 492, 494, 498, 499, 541, 575, 579, 583, 729, 900, 913, 10035, 10038, 10055, 10071, 10082, 10110, 10222, 10235, 10327, 10346, 10370, 10424, 10469, 10591, 10696, 10699, 10789, 10812, 10922, 10924, 10929, 10931, 10970, 11152, 11172, 11185, 11192, 11219, 11233, 11462, 11530, 11727, 11764, 11799, 11804, 11805, 11827, 11854, 11875, 11900, 11917, 11934, 11936, 11942, 11984, 11988, 11991, 11995, 12015, 12149, 12149, 12149, 12149, 12149, 12149, 12372, 12372, 12372, 12372, 12372**

# Kruskal’s Minimum Spanning Tree Algorithm

Standard__Minimum Spanning Tree__

To form an MST(Minimum Spanning Tree) follow this procedure,

1. Begin with a connected graph G.

2. E is the set of all edges of different weights, from G.

3. Sort edges of E in the ascending order of their weights.

4. Go through each member(edge) of E and see if the nodes of that edge is already connected or not.

5. If they aren’t connected, connect them and include that member of E(edge) int MST.

6. Continue this process untill you’ve got n-1 edges(in case of n nodes).

An implementation in C++ using Disjoint Set data structure, is shown

#include <cstdio> #include <algorithm> #define MAX_node 100000 using namespace std; struct edg{ int a,b,w; bool operator < (const edg &b) const{ return w<b.w; } }E[MAX_node+1]; int Prev[MAX_node+1]; int parent(int a){ if(a==Prev[a]) return a; return Prev[a]=parent(Prev[a]); } int main(){ int node,edge; while(scanf("%d%d",&node,&edge)){ int TOTAL=0; for(int i=1;i<=node;i++) Prev[i]=i;//* for(int i=0;i<edge;i++) scanf("%d%d%d",&E[i].a,&E[i].b,&E[i].w);//** sort(E,E+edge);//*** for(int i=0; i<edge; i++ ){ int u=parent(E[i].a);//**** int v=parent(E[i].b); if(u!=v){ TOTAL+=E[i].w; Prev[u]=v;//***** } } printf("Total Cost of MST %d\n",TOTAL); } return 0; } /* * Making each node it's own parent ** Input edges in the format "node1 node2 weight" *** Sorting them in the ascending order of weight **** Find the current parent of a and b ***** If the nodes of that edge is not connected yet, Connect them. */

if you don’t know Maximum possible number of nodes, then just use a vector(which is a bit slower) of type ‘edg’.

**Related Problems**

MST(spoj)

Dark Roads(UVa)

Audiophobia(UVa)

Connect the Campus(UVa)

Highways(UVa)

__Maximum Spanning Tree__

To get a maximum spanning tree, the procedure is almost same. The only difference is that, you got to sort members of E in the descending order of their weights.

**Related Problems
**Heavy Cargo(UVa)

__Second Best Minimum Spanning Tree__

There may be some other better procedure to find the second best MST, but this is the one I’ve used.

1. First form an MST of graph G, and mark the edges which formes the MST.

2. Then for each member edge of the MST, Form another MST without using that particular member.

3. Thus, u need to form n-1 (in case of n nodes) ‘another’ MSTs and consider the minimun among them.

**Related Problems**

Is There A Second Way Left ?(UVa)

ACM contest and Blackout(UVa)

# Floyd Warshall

StandardFloyd-Warshall algorithm, a formula consisting of the core is very simple. A, B, C, I suppose we have 3 points. In this case, the shortest distance between A and C (distance (A, C), distance (A, B) + distance (B, C)) is up. Floyd-Warshall’Ä± need to apply to a table. The size of this table, depending on the number of points to be determined. We got one point, the table size N * N N

int[,] table = new int[5,5];

On the basis of the algorithm used for the function of the input for this table are the values at the maximum. The distance of each point of self-0, the distance to other points, we will begin by accepting the infinite.

int INFINITY = 9999999; int N = 5; for (int i = 0; i < N; i++) for(int j = 0; j < N; j++) table[i,j] = i == j ? 0 : INFINITY;

After this operation, the value of the table will be as follows.

table | 1 |
2 |
3 |
4 |
5 |

1 |
0 | INF | INF | INF | INF |

2 |
INF | 0 | INF | INF | INF |

3 |
INF | INF | 0 | INF | INF |

4 |
INF | INF | INF | 0 | INF |

5 |
INF | INF | INF | INF | 0 |

Second, to keep the connection between the points and to build the matrix of contiguity for questioning. If you have an edge from one point to another entry in the table that would give a value. For example, point 3 and point 4, one side has 2 points. Therefore, our statements [2,3] = [2.4] = 1 = [3.2] = [4.2]. GrafÄ±mÄ±z no way we obtain for the diagonal matrix based on contiguity should be symmetrical. 1 to 4, because to have the edge in the 4 to 1, this also means there are also edges. Our example is a way you could tell it had graphs. After this, the final version of the table will be as follows:

table | 1 |
2 |
3 |
4 |
5 |

1 |
0 | INF | INF | 1 | INF |

2 |
INF | 0 | 1 | 1 | INF |

3 |
INF | 1 | 0 | 1 | INF |

4 |
1 | 1 | 1 | 0 | 1 |

5 |
INF | INF | INF | 1 | 0 |

Floyd-Warshall can now apply the formula:

for( int k = 0; k < N; k++) for( int i = 0; i < N; i++) for( int j = 0; j < N; j++) table[i,j] = Math.Min(table[i,j], table[i,k] + table[k,j]);

That’s it. After this, our table will be as final.

table | 1 |
2 |
3 |
4 |
5 |

1 |
0 | 2 | 2 | 1 | 2 |

2 |
2 | 0 | 1 | 1 | 2 |

3 |
2 | 1 | 0 | 1 | 2 |

4 |
1 | 1 | 1 | 0 | 1 |

5 |
2 | 2 | 2 | 1 | 0 |

Now using the table between the two points (a, b) can query the shortest distance. table [a, b] = table [b, a].

# atod function

Standard

**atod** function’s work is identical to **atoi**‘s. But this one is for **doubles**

// for texting/ example purposes #include <iostream> // for cout and endl #include <cmath> // for pow using namespace std; // so we don't have to do std::coud or std::endl //end testing/ example purposes char* substr(char* str, int start, int end){ char* a = new char[1+(end-start)]; // we need a new char array for the return for(int i=start; i<end; i++){ // loop through the string a[i-start] = str[i]; // set the characters in the new char array to those from the old one compensating for the substring } a[end-start] = '\0'; // add the null character, so we can output return a; // return } double atod(char* a){ double retVal = atoi(a); // start off getting the number, assuming it is a valid string to use atoi on. int start = 0; int end = 0; for(int i=0; a[i] != '\0'; i++){ // loop through the string to find the positions of the decimal portion, if there is one if(a[i] == '.' && start == 0){ start = i+1; // set the start position to 1 more than the current (avoids a char as the first character - we want a digit) } else if(start != 0 && (a[i] < '0' || a[i] > '9')){ // make sure that start is set and that we aren't looking at digits end = i; // if so, set the end location for the substring break; // we don't need to continue anymore - break out of the loop } } if(end > start){ // avoids substring problems. char* decimal = substr(a, start, end); // get the string that is after the decimal point int dec = atoi(decimal); // make it an integer int power = end-start; // find the power of 10 we need to divide by retVal += ((double)dec)/(pow(10.0, (double)power)); // divide and add to the return value (thus making it a true double) } return retVal; // return - simple enough } // for testing/ example purposes int main(){ cout << atod("127.02501 test") << endl; // test it out on a valid character stream return 0; } // end testing/ example purposes

# Quick Sort : Sorting array of Strings, Integers and Structs

Standardvoid qsort(void *base, size_t nel, size_t width, int (*compar)(const void *, const void *));

â– base â€” is a pointer to the beginning of data array

â– nel â€” is a number of elements

â– width â€” is a size of each element (in bytes)

â– compar â€” is a callback function (pointer to function), which does comparison and returns positive or negative integer depending on result.

This example contains three separate functions sort_integers_example(), sort_cstrings_example() and sort_structs_example().

â– sort_integers_example() uses int_cmp() as compar callback. Additional function print_int_array is used for printing integer array contents.

â– sort_cstrings_example() uses cstring_cmp() as compar callback. Additional function print_cstring_array is used for printing string array contents.

â– sort_structs_example() uses struct_cmp_by_price() and struct_cmp_by_product() as compar callbacks. Additional function print_struct_array is used for printing array of struct.

#include <stdio.h> #include <stdlib.h> #include <string.h> /* qsort int comparison function */ int int_cmp(const void *a, const void *b) { const int *ia = (const int *)a; // casting pointer types const int *ib = (const int *)b; return *ia - *ib; /* integer comparison: returns negative if b > a and positive if a > b */ } /* integer array printing function */ void print_int_array(const int *array, size_t len) { size_t i; for(i=0; i<len; i++) printf("%d | ", array[i]); putchar('\n'); } /* sorting integers using qsort() example */ void sort_integers_example() { int numbers[] = { 7, 3, 4, 1, -1, 23, 12, 43, 2, -4, 5 }; size_t numbers_len = sizeof(numbers)/sizeof(int); puts("*** Integer sorting..."); /* print original integer array */ print_int_array(numbers, numbers_len); /* sort array using qsort functions */ qsort(numbers, numbers_len, sizeof(int), int_cmp); /* print sorted integer array */ print_int_array(numbers, numbers_len); } /* qsort C-string comparison function */ int cstring_cmp(const void *a, const void *b) { const char **ia = (const char **)a; const char **ib = (const char **)b; return strcmp(*ia, *ib); /* strcmp functions works exactly as expected from comparison function */ } /* C-string array printing function */ void print_cstring_array(char **array, size_t len) { size_t i; for(i=0; i<len; i++) printf("%s | ", array[i]); putchar('\n'); } /* sorting C-strings array using qsort() example */ void sort_cstrings_example() { char *strings[] = { "Zorro", "Alex", "Celine", "Bill", "Forest", "Dexter" }; size_t strings_len = sizeof(strings) / sizeof(char *); /** STRING */ puts("*** String sorting..."); /* print original string array */ print_cstring_array(strings, strings_len); /* sort array using qsort functions */ qsort(strings, strings_len, sizeof(char *), cstring_cmp); /* print sorted string array */ print_cstring_array(strings, strings_len); } /* an example of struct */ struct st_ex { char product[16]; float price; }; /* qsort struct comparision function (price float field) */ int struct_cmp_by_price(const void *a, const void *b) { struct st_ex *ia = (struct st_ex *)a; struct st_ex *ib = (struct st_ex *)b; return (int)(100.f*ia->price - 100.f*ib->price); /* float comparison: returns negative if b > a and positive if a > b. We multiplied result by 100.0 to preserve decimal fraction */ } /* qsort struct comparision function (product C-string field) */ int struct_cmp_by_product(const void *a, const void *b) { struct st_ex *ia = (struct st_ex *)a; struct st_ex *ib = (struct st_ex *)b; return strcmp(ia->product, ib->product); /* strcmp functions works exactly as expected from comparison function */ } /* Example struct array printing function */ void print_struct_array(struct st_ex *array, size_t len) { size_t i; for(i=0; i<len; i++) printf("[ product: %s \t price: $%.2f ]\n", array[i].product, array[i].price); puts("--"); } /* sorting structs using qsort() example */ void sort_structs_example(void) { struct st_ex structs[] = {{"mp3 player", 299.0f}, {"plasma tv", 2200.0f}, {"notebook", 1300.0f}, {"smartphone", 499.99f}, {"dvd player", 150.0f}, {"matches", 0.2f }}; size_t structs_len = sizeof(structs) / sizeof(struct st_ex); puts("*** Struct sorting (price)..."); /* print original struct array */ print_struct_array(structs, structs_len); /* sort array using qsort functions */ qsort(structs, structs_len, sizeof(struct st_ex), struct_cmp_by_price); /* print sorted struct array */ print_struct_array(structs, structs_len); puts("*** Struct sorting (product)..."); /* resort using other comparision function */ qsort(structs, structs_len, sizeof(struct st_ex), struct_cmp_by_product); /* print sorted struct array */ print_struct_array(structs, structs_len); } /* MAIN program (calls all other examples) */ int main() { /* run all example functions */ sort_integers_example(); sort_cstrings_example(); sort_structs_example(); return 0; }

Execution result:

*** Integer sorting…

7 | 3 | 4 | 1 | -1 | 23 | 12 | 43 | 2 | -4 | 5 |

-4 | -1 | 1 | 2 | 3 | 4 | 5 | 7 | 12 | 23 | 43 |

*** String sorting…

Zorro | Alex | Celine | Bill | Forest | Dexter |

Alex | Bill | Celine | Dexter | Forest | Zorro |

*** Struct sorting (price)…

[ product: mp3 player price: $299.00 ]

[ product: plasma tv price: $2200.00 ]

[ product: notebook price: $1300.00 ]

[ product: smartphone price: $499.99 ]

[ product: dvd player price: $150.00 ]

[ product: matches price: $0.20 ]

—

[ product: matches price: $0.20 ]

[ product: dvd player price: $150.00 ]

[ product: mp3 player price: $299.00 ]

[ product: smartphone price: $499.99 ]

[ product: notebook price: $1300.00 ]

[ product: plasma tv price: $2200.00 ]

—

*** Struct sorting (product)…

[ product: dvd player price: $150.00 ]

[ product: matches price: $0.20 ]

[ product: mp3 player price: $299.00 ]

[ product: notebook price: $1300.00 ]

[ product: plasma tv price: $2200.00 ]

[ product: smartphone price: $499.99 ]

—

# Online compiler/interpreter/IDE

StandardToday, I came across ideone.com, which is very similar to the above, except that it allows providing input to the program! Yay! You type (or paste) the program in a text area as in codepad, choose your language from the list, and then click on “click here to paste input (stdin) or additional note”. Whatever you type here becomes the input to your program. That’s a neat solution to the problem of providing input to remotely-evaluated programs.

And it supports “more than 40 languages”, including Assembler, Common Lisp, and even Whitespace (of course the boring old C, C++, Java, Perl, Python, etc. are there too). It has other goodies like syntax highlighting for all these languages, ‘private’ pasting for times when you don’t want others to see the code, etc. The site is quite very well done.

While we’re in the topic, let me also add two more online code evaluation tools (compilers/interpreters):

* Lord of the REPLs: This is a Read-Eval-Print-Loop from Google, where each line you enter is evaluated immediately. Despite the fancy “Lord” name and the Google brand, I haven’t found this very useful mainly because: it doesn’t preserve function definitions or variables’ values after you evaluate them, unlike other REPLs. This makes it hard to run anything more than trivial “hello world” programs. Also, I found it quite buggy at times.

* “Compile & Execute”: This is somewhat similar to ideone, allowing you to enter your own input and having a choice of a similar number of languages. However, it doesn’t have a ‘private’ pasting option, and has syntax highlighting for only a few languages. This leads to weird highlighting at times: if you choose to paste Perl code, the Highlight choice remains in cpp (which is the default), so your Perl code gets highlighted as C++ code! Sloppy design like this makes me think this site might not be very well designed.

These two are the only generic code evaluation tools I could find. If you find that none of these do it for you, try googling for something specific to your language. For example, for Python, searching for ‘python online (IDE OR compiler OR interpreter)’ gives a lot of good results.

If you know some other online code evaluation tool, or have experience with any of the above, do share it in the comments. Thanks!